Base | Representation |
---|---|
bin | 11011010010011010110100… |
… | …110101100110000001111001 |
3 | 120201221010120000122021102102 |
4 | 123102122310311212001321 |
5 | 111212243121043224423 |
6 | 1103125114333113145 |
7 | 34164440161404326 |
oct | 3322326465460171 |
9 | 521833500567372 |
10 | 120013010133113 |
11 | 3527026053a839 |
12 | 115633aa3287b5 |
13 | 51c72419389a6 |
14 | 218c936cb5b4d |
15 | dd1c31909c28 |
hex | 6d26b4d66079 |
120013010133113 has 2 divisors, whose sum is σ = 120013010133114. Its totient is φ = 120013010133112.
The previous prime is 120013010133101. The next prime is 120013010133161. The reversal of 120013010133113 is 311331010310021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116415209209744 + 3597800923369 = 10789588^2 + 1896787^2 .
It is a cyclic number.
It is not a de Polignac number, because 120013010133113 - 28 = 120013010132857 is a prime.
It is not a weakly prime, because it can be changed into another prime (120013010133173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006505066556 + 60006505066557.
It is an arithmetic number, because the mean of its divisors is an integer number (60006505066557).
Almost surely, 2120013010133113 is an apocalyptic number.
It is an amenable number.
120013010133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
120013010133113 is an equidigital number, since it uses as much as digits as its factorization.
120013010133113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 120013010133113 its reverse (311331010310021), we get a palindrome (431344020443134).
The spelling of 120013010133113 in words is "one hundred twenty trillion, thirteen billion, ten million, one hundred thirty-three thousand, one hundred thirteen".
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