Base | Representation |
---|---|
bin | 1010111010100100010111… |
… | …0101010101000101001011 |
3 | 1120111022110221111211110011 |
4 | 2232221011311111011023 |
5 | 3033112140404423112 |
6 | 41305154212532351 |
7 | 2346031440552352 |
oct | 256510565250513 |
9 | 46438427454404 |
10 | 12001310232907 |
11 | 39077aa831216 |
12 | 1419b266210b7 |
13 | 690945c9b428 |
14 | 2d6c1ba04999 |
15 | 15c2ace82aa7 |
hex | aea45d5514b |
12001310232907 has 2 divisors, whose sum is σ = 12001310232908. Its totient is φ = 12001310232906.
The previous prime is 12001310232881. The next prime is 12001310233021. The reversal of 12001310232907 is 70923201310021.
12001310232907 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12001310232907 is a prime.
It is not a weakly prime, because it can be changed into another prime (12001310272907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000655116453 + 6000655116454.
It is an arithmetic number, because the mean of its divisors is an integer number (6000655116454).
Almost surely, 212001310232907 is an apocalyptic number.
12001310232907 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001310232907 is an equidigital number, since it uses as much as digits as its factorization.
12001310232907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 31.
Adding to 12001310232907 its reverse (70923201310021), we get a palindrome (82924511542928).
The spelling of 12001310232907 in words is "twelve trillion, one billion, three hundred ten million, two hundred thirty-two thousand, nine hundred seven".
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