Base | Representation |
---|---|
bin | 11011010010011010111100… |
… | …101001111111101000101001 |
3 | 120201221010220011110202021101 |
4 | 123102122330221333220221 |
5 | 111212243403133404433 |
6 | 1103125135340441401 |
7 | 34164443343366241 |
oct | 3322327451775051 |
9 | 521833804422241 |
10 | 120013141309993 |
11 | 35270318595988 |
12 | 11563426249261 |
13 | 51c7262b77049 |
14 | 218c94a4a0b21 |
15 | dd1c3d1bc07d |
hex | 6d26bca7fa29 |
120013141309993 has 2 divisors, whose sum is σ = 120013141309994. Its totient is φ = 120013141309992.
The previous prime is 120013141309967. The next prime is 120013141310003. The reversal of 120013141309993 is 399903141310021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80440951956544 + 39572189353449 = 8968888^2 + 6290643^2 .
It is a cyclic number.
It is not a de Polignac number, because 120013141309993 - 225 = 120013107755561 is a prime.
It is not a weakly prime, because it can be changed into another prime (120013141309903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006570654996 + 60006570654997.
It is an arithmetic number, because the mean of its divisors is an integer number (60006570654997).
Almost surely, 2120013141309993 is an apocalyptic number.
It is an amenable number.
120013141309993 is a deficient number, since it is larger than the sum of its proper divisors (1).
120013141309993 is an equidigital number, since it uses as much as digits as its factorization.
120013141309993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 157464, while the sum is 46.
The spelling of 120013141309993 in words is "one hundred twenty trillion, thirteen billion, one hundred forty-one million, three hundred nine thousand, nine hundred ninety-three".
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