12001323141433 has 4 divisors (see below), whose sum is σ = 12009721549540. Its totient is φ = 11992924733328.

The previous prime is 12001323141419. The next prime is 12001323141449. The reversal of 12001323141433 is 33414132310021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4155514866064 + 7845808275369 = 2038508^2 + 2801037^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12001323141433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12001323141403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4199201910 + ... + 4199204767.

It is an arithmetic number, because the mean of its divisors is an integer number (3002430387385).

Almost surely, 2^{12001323141433} is an apocalyptic number.

It is an amenable number.

12001323141433 is a deficient number, since it is larger than the sum of its proper divisors (8398408107).

12001323141433 is an equidigital number, since it uses as much as digits as its factorization.

12001323141433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8398408106.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 12001323141433 its reverse (33414132310021), we get a palindrome (45415455451454).

The spelling of 12001323141433 in words is "twelve trillion, one billion, three hundred twenty-three million, one hundred forty-one thousand, four hundred thirty-three".