Base | Representation |
---|---|
bin | 11011010010011011000110… |
… | …110110011001010011101001 |
3 | 120201221011100002021121210001 |
4 | 123102123012312121103221 |
5 | 111212244230424124113 |
6 | 1103125204330223001 |
7 | 34164450521145550 |
oct | 3322330666312351 |
9 | 521834302247701 |
10 | 120013312333033 |
11 | 352703a6087039 |
12 | 11563473584a61 |
13 | 51c728c426c02 |
14 | 218c96509cd97 |
15 | dd1c4d2007dd |
hex | 6d26c6d994e9 |
120013312333033 has 4 divisors (see below), whose sum is σ = 137158071237760. Its totient is φ = 102868553428308.
The previous prime is 120013312333003. The next prime is 120013312333087. The reversal of 120013312333033 is 330333213310021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120013312333033 is a prime.
It is a super-2 number, since 2×1200133123330332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120013312332992 and 120013312333010.
It is not an unprimeable number, because it can be changed into a prime (120013312333003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8572379452353 + ... + 8572379452366.
It is an arithmetic number, because the mean of its divisors is an integer number (34289517809440).
Almost surely, 2120013312333033 is an apocalyptic number.
It is an amenable number.
120013312333033 is a deficient number, since it is larger than the sum of its proper divisors (17144758904727).
120013312333033 is an equidigital number, since it uses as much as digits as its factorization.
120013312333033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17144758904726.
The product of its (nonzero) digits is 8748, while the sum is 28.
Adding to 120013312333033 its reverse (330333213310021), we get a palindrome (450346525643054).
The spelling of 120013312333033 in words is "one hundred twenty trillion, thirteen billion, three hundred twelve million, three hundred thirty-three thousand, thirty-three".
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