Search a number
-
+
12002013430003 = 68317572494041
BaseRepresentation
bin1010111010100110111110…
…1111110100000011110011
31120111101021221200221112001
42232221233233310003303
53033120110414230003
641305352052514431
72346055036620562
oct256515757640363
946441257627461
1012002013430003
113908030764643
12141a0a201ba17
13690a28889a9c
142d6c87171bd9
1515c2eea8761d
hexaea6fbf40f3

12002013430003 has 4 divisors (see below), whose sum is σ = 12019585924728. Its totient is φ = 11984440935280.

The previous prime is 12002013429961. The next prime is 12002013430009. The reversal of 12002013430003 is 30003431020021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12002013430003 - 241 = 9802990174451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12002013430009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8786246338 + ... + 8786247703.

It is an arithmetic number, because the mean of its divisors is an integer number (3004896481182).

Almost surely, 212002013430003 is an apocalyptic number.

12002013430003 is a deficient number, since it is larger than the sum of its proper divisors (17572494725).

12002013430003 is an equidigital number, since it uses as much as digits as its factorization.

12002013430003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17572494724.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 12002013430003 its reverse (30003431020021), we get a palindrome (42005444450024).

The spelling of 12002013430003 in words is "twelve trillion, two billion, thirteen million, four hundred thirty thousand, three".

Divisors: 1 683 17572494041 12002013430003