Base | Representation |
---|---|
bin | 10001011101110010001… |
… | …010011000100001110001 |
3 | 11020201221210010012001212 |
4 | 101131302022120201301 |
5 | 124131013031400423 |
6 | 2315211443205505 |
7 | 152466231605552 |
oct | 21356212304161 |
9 | 4221853105055 |
10 | 1200211200113 |
11 | 423008a29942 |
12 | 174738376895 |
13 | 89244293ba3 |
14 | 4213a5c4329 |
15 | 21348508578 |
hex | 11772298871 |
1200211200113 has 2 divisors, whose sum is σ = 1200211200114. Its totient is φ = 1200211200112.
The previous prime is 1200211199981. The next prime is 1200211200121. The reversal of 1200211200113 is 3110021120021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1180388812849 + 19822387264 = 1086457^2 + 140792^2 .
It is an emirp because it is prime and its reverse (3110021120021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1200211200113 - 230 = 1199137458289 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1200211200173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600105600056 + 600105600057.
It is an arithmetic number, because the mean of its divisors is an integer number (600105600057).
Almost surely, 21200211200113 is an apocalyptic number.
It is an amenable number.
1200211200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200211200113 is an equidigital number, since it uses as much as digits as its factorization.
1200211200113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1200211200113 its reverse (3110021120021), we get a palindrome (4310232320134).
The spelling of 1200211200113 in words is "one trillion, two hundred billion, two hundred eleven million, two hundred thousand, one hundred thirteen".
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