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12002131993 is a prime number
BaseRepresentation
bin10110010110110001…
…00000000000011001
31010222110010110220011
423023120200000121
5144040021210433
65302543201521
7603265303315
oct131330400031
933873113804
1012002131993
1150a9988455
1223ab5a62a1
131193730067
1481c014b45
154a3a423cd
hex2cb620019

12002131993 has 2 divisors, whose sum is σ = 12002131994. Its totient is φ = 12002131992.

The previous prime is 12002131931. The next prime is 12002132003. The reversal of 12002131993 is 39913120021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6862962649 + 5139169344 = 82843^2 + 71688^2 .

It is a cyclic number.

It is not a de Polignac number, because 12002131993 - 29 = 12002131481 is a prime.

It is not a weakly prime, because it can be changed into another prime (12002131913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001065996 + 6001065997.

It is an arithmetic number, because the mean of its divisors is an integer number (6001065997).

Almost surely, 212002131993 is an apocalyptic number.

It is an amenable number.

12002131993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12002131993 is an equidigital number, since it uses as much as digits as its factorization.

12002131993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 31.

The spelling of 12002131993 in words is "twelve billion, two million, one hundred thirty-one thousand, nine hundred ninety-three".