Base | Representation |
---|---|
bin | 11011010010100010100100… |
… | …010001010001111111101011 |
3 | 120201221221000022002121021110 |
4 | 123102202210101101333223 |
5 | 111212412131430104003 |
6 | 1103133011215441403 |
7 | 34165153151151003 |
oct | 3322424421217753 |
9 | 521857008077243 |
10 | 120021322113003 |
11 | 35273836424303 |
12 | 11564b29b26263 |
13 | 51c7c679b269c |
14 | 218d0c4b91003 |
15 | dd206b4cda03 |
hex | 6d28a4451feb |
120021322113003 has 8 divisors (see below), whose sum is σ = 160174841592208. Its totient is φ = 79941008687904.
The previous prime is 120021322112971. The next prime is 120021322113019. The reversal of 120021322113003 is 300311223120021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 120021322113003 - 25 = 120021322112971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120021322117003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18301509700 + ... + 18301516257.
It is an arithmetic number, because the mean of its divisors is an integer number (20021855199026).
Almost surely, 2120021322113003 is an apocalyptic number.
120021322113003 is a deficient number, since it is larger than the sum of its proper divisors (40153519479205).
120021322113003 is a wasteful number, since it uses less digits than its factorization.
120021322113003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36603027053.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 120021322113003 its reverse (300311223120021), we get a palindrome (420332545233024).
The spelling of 120021322113003 in words is "one hundred twenty trillion, twenty-one billion, three hundred twenty-two million, one hundred thirteen thousand, three".
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