Search a number
-
+
12002200312131 = 321333577812459
BaseRepresentation
bin1010111010100111101011…
…1000101101100101000011
31120111101202222100112121100
42232221322320231211003
53033121001234442011
641305422410225443
72346062466241461
oct256517270554503
946441688315540
1012002200312131
1139081171a7987
12141a134725283
13690a58500323
142d6ca3cdb831
1515c31119ed56
hexaea7ae2d943

12002200312131 has 6 divisors (see below), whose sum is σ = 17336511561980. Its totient is φ = 8001466874748.

The previous prime is 12002200312099. The next prime is 12002200312159. The reversal of 12002200312131 is 13121300220021.

12002200312131 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 220 + 0 + 312 + 131 = 666.

It is not a de Polignac number, because 12002200312131 - 25 = 12002200312099 is a prime.

It is a super-2 number, since 2×120022003121312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12002200311131) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 666788906221 + ... + 666788906238.

Almost surely, 212002200312131 is an apocalyptic number.

12002200312131 is a deficient number, since it is larger than the sum of its proper divisors (5334311249849).

12002200312131 is a wasteful number, since it uses less digits than its factorization.

12002200312131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1333577812465 (or 1333577812462 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12002200312131 its reverse (13121300220021), we get a palindrome (25123500532152).

The spelling of 12002200312131 in words is "twelve trillion, two billion, two hundred million, three hundred twelve thousand, one hundred thirty-one".

Divisors: 1 3 9 1333577812459 4000733437377 12002200312131