Base | Representation |
---|---|
bin | 1010111010100111101011… |
… | …1000101101100101000011 |
3 | 1120111101202222100112121100 |
4 | 2232221322320231211003 |
5 | 3033121001234442011 |
6 | 41305422410225443 |
7 | 2346062466241461 |
oct | 256517270554503 |
9 | 46441688315540 |
10 | 12002200312131 |
11 | 39081171a7987 |
12 | 141a134725283 |
13 | 690a58500323 |
14 | 2d6ca3cdb831 |
15 | 15c31119ed56 |
hex | aea7ae2d943 |
12002200312131 has 6 divisors (see below), whose sum is σ = 17336511561980. Its totient is φ = 8001466874748.
The previous prime is 12002200312099. The next prime is 12002200312159. The reversal of 12002200312131 is 13121300220021.
12002200312131 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 220 + 0 + 312 + 131 = 666.
It is not a de Polignac number, because 12002200312131 - 25 = 12002200312099 is a prime.
It is a super-2 number, since 2×120022003121312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12002200311131) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 666788906221 + ... + 666788906238.
Almost surely, 212002200312131 is an apocalyptic number.
12002200312131 is a deficient number, since it is larger than the sum of its proper divisors (5334311249849).
12002200312131 is a wasteful number, since it uses less digits than its factorization.
12002200312131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1333577812465 (or 1333577812462 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 12002200312131 its reverse (13121300220021), we get a palindrome (25123500532152).
The spelling of 12002200312131 in words is "twelve trillion, two billion, two hundred million, three hundred twelve thousand, one hundred thirty-one".
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