Base | Representation |
---|---|
bin | 1010111010100111101011… |
… | …1000101101111000000011 |
3 | 1120111101202222100121021101 |
4 | 2232221322320231320003 |
5 | 3033121001240011342 |
6 | 41305422410235231 |
7 | 2346062466245146 |
oct | 256517270557003 |
9 | 46441688317241 |
10 | 12002200313347 |
11 | 39081171a8892 |
12 | 141a134725b17 |
13 | 690a58500a4a |
14 | 2d6ca3cdc05d |
15 | 15c3111a03b7 |
hex | aea7ae2de03 |
12002200313347 has 2 divisors, whose sum is σ = 12002200313348. Its totient is φ = 12002200313346.
The previous prime is 12002200313269. The next prime is 12002200313351. The reversal of 12002200313347 is 74331300220021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12002200313347 - 27 = 12002200313219 is a prime.
It is not a weakly prime, because it can be changed into another prime (12002200313357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001100156673 + 6001100156674.
It is an arithmetic number, because the mean of its divisors is an integer number (6001100156674).
Almost surely, 212002200313347 is an apocalyptic number.
12002200313347 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002200313347 is an equidigital number, since it uses as much as digits as its factorization.
12002200313347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 12002200313347 its reverse (74331300220021), we get a palindrome (86333500533368).
The spelling of 12002200313347 in words is "twelve trillion, two billion, two hundred million, three hundred thirteen thousand, three hundred forty-seven".
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