12002201403 has 4 divisors (see below), whose sum is σ = 16002935208. Its totient is φ = 8001467600.

The previous prime is 12002201401. The next prime is 12002201411. The reversal of 12002201403 is 30410220021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12002201403 - 2¹ = 12002201401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12002201401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000366898 + ... + 2000366903.

It is an arithmetic number, because the mean of its divisors is an integer number (4000733802).

Almost surely, 2^12002201403 is an apocalyptic number.

12002201403 is a deficient number, since it is larger than the sum of its proper divisors (4000733805).

12002201403 is an equidigital number, since it uses as much as digits as its factorization.

12002201403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4000733804.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 12002201403 its reverse (30410220021), we get a palindrome (42412421424).

The spelling of 12002201403 in words is "twelve billion, two million, two hundred one thousand, four hundred three".