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12002335511417 is a prime number
BaseRepresentation
bin1010111010101000001011…
…1100011101001101111001
31120111102010101202101011022
42232222002330131031321
53033121240342331132
641305444040112225
72346066030355466
oct256520274351571
946442111671138
1012002335511417
113908186550129
12141a171a65675
13690a7a5194c4
142d6cb7c5266d
1515c31cea8e12
hexaea82f1d379

12002335511417 has 2 divisors, whose sum is σ = 12002335511418. Its totient is φ = 12002335511416.

The previous prime is 12002335511347. The next prime is 12002335511447. The reversal of 12002335511417 is 71411553320021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9945073123561 + 2057262387856 = 3153581^2 + 1434316^2 .

It is a cyclic number.

It is not a de Polignac number, because 12002335511417 - 210 = 12002335510393 is a prime.

It is not a weakly prime, because it can be changed into another prime (12002335511447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001167755708 + 6001167755709.

It is an arithmetic number, because the mean of its divisors is an integer number (6001167755709).

Almost surely, 212002335511417 is an apocalyptic number.

It is an amenable number.

12002335511417 is a deficient number, since it is larger than the sum of its proper divisors (1).

12002335511417 is an equidigital number, since it uses as much as digits as its factorization.

12002335511417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 35.

Adding to 12002335511417 its reverse (71411553320021), we get a palindrome (83413888831438).

The spelling of 12002335511417 in words is "twelve trillion, two billion, three hundred thirty-five million, five hundred eleven thousand, four hundred seventeen".