12003104411433 has 24 divisors (see below), whose sum is σ = 17469851686560. Its totient is φ = 7941178889280.

The previous prime is 12003104411411. The next prime is 12003104411453. The reversal of 12003104411433 is 33411440130021.

12003104411433 is a `hidden beast` number, since 1 + 200 + 3 + 1 + 0 + 4 + 411 + 43 + 3 = 666.

12003104411433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 12003104411433 - 2²⁰ = 12003103362857 is a prime.

It is a super-2 number, since 2×12003104411433² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12003104411397 and 12003104411406.

It is not an unprimeable number, because it can be changed into a prime (12003104411453) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 988878 + ... + 4998408.

It is an arithmetic number, because the mean of its divisors is an integer number (727910486940).

Almost surely, 2^{12003104411433} is an apocalyptic number.

It is an amenable number.

12003104411433 is a deficient number, since it is larger than the sum of its proper divisors (5466747275127).

12003104411433 is a wasteful number, since it uses less digits than its factorization.

12003104411433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4012069 (or 4012066 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 12003104411433 its reverse (33411440130021), we get a palindrome (45414544541454).

The spelling of 12003104411433 in words is "twelve trillion, three billion, one hundred four million, four hundred eleven thousand, four hundred thirty-three".