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1200311102121 = 3400103700707
BaseRepresentation
bin10001011101111000000…
…111011110101010101001
311020202012202002201212020
4101131320013132222221
5124131214120231441
62315225412335053
7152501554012215
oct21357007365251
94222182081766
101200311102121
1142305a36378a
12174765914489
138925bba1bc1
144214998b945
152135218de66
hex117781deaa9

1200311102121 has 4 divisors (see below), whose sum is σ = 1600414802832. Its totient is φ = 800207401412.

The previous prime is 1200311102059. The next prime is 1200311102131. The reversal of 1200311102121 is 1212011130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200311102121 - 27 = 1200311101993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1200311102121.

It is not an unprimeable number, because it can be changed into a prime (1200311102131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200051850351 + ... + 200051850356.

It is an arithmetic number, because the mean of its divisors is an integer number (400103700708).

Almost surely, 21200311102121 is an apocalyptic number.

It is an amenable number.

1200311102121 is a deficient number, since it is larger than the sum of its proper divisors (400103700711).

1200311102121 is an equidigital number, since it uses as much as digits as its factorization.

1200311102121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400103700710.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1200311102121 its reverse (1212011130021), we get a palindrome (2412322232142).

The spelling of 1200311102121 in words is "one trillion, two hundred billion, three hundred eleven million, one hundred two thousand, one hundred twenty-one".

Divisors: 1 3 400103700707 1200311102121