1200314013131 has 2 divisors, whose sum is σ = 1200314013132. Its totient is φ = 1200314013130.

The previous prime is 1200314013121. The next prime is 1200314013139. The reversal of 1200314013131 is 1313104130021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1200314013131 - 2²⁶ = 1200246904267 is a prime.

It is a super-2 number, since 2×1200314013131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1200314013139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600157006565 + 600157006566.

It is an arithmetic number, because the mean of its divisors is an integer number (600157006566).

Almost surely, 2^{1200314013131} is an apocalyptic number.

1200314013131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200314013131 is an equidigital number, since it uses as much as digits as its factorization.

1200314013131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1200314013131 its reverse (1313104130021), we get a palindrome (2513418143152).

The spelling of 1200314013131 in words is "one trillion, two hundred billion, three hundred fourteen million, thirteen thousand, one hundred thirty-one".