1200314013231 has 32 divisors (see below), whose sum is σ = 1713403296000. Its totient is φ = 745157622528.

The previous prime is 1200314013191. The next prime is 1200314013233. The reversal of 1200314013231 is 1323104130021.

It is not a de Polignac number, because 1200314013231 - 2⁷ = 1200314013103 is a prime.

It is a super-2 number, since 2×1200314013231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1200314013198 and 1200314013207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200314013233) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 41192275 + ... + 41221403.

It is an arithmetic number, because the mean of its divisors is an integer number (53543853000).

Almost surely, 2^{1200314013231} is an apocalyptic number.

1200314013231 is a deficient number, since it is larger than the sum of its proper divisors (513089282769).

1200314013231 is a wasteful number, since it uses less digits than its factorization.

1200314013231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41463.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1200314013231 its reverse (1323104130021), we get a palindrome (2523418143252).

The spelling of 1200314013231 in words is "one trillion, two hundred billion, three hundred fourteen million, thirteen thousand, two hundred thirty-one".