Base | Representation |
---|---|
bin | 10001011101111000010… |
… | …011110000110011010101 |
3 | 11020202012222011022212221 |
4 | 101131320103300303111 |
5 | 124131220431302013 |
6 | 2315230005342341 |
7 | 152501623253053 |
oct | 21357023606325 |
9 | 4222188138787 |
10 | 1200314322133 |
11 | 423061162a53 |
12 | 174766a079b1 |
13 | 8925c75b734 |
14 | 4214a1891d3 |
15 | 213525c808d |
hex | 117784f0cd5 |
1200314322133 has 16 divisors (see below), whose sum is σ = 1322616176640. Its totient is φ = 1084958506800.
The previous prime is 1200314322113. The next prime is 1200314322143. The reversal of 1200314322133 is 3312234130021.
It is a cyclic number.
It is not a de Polignac number, because 1200314322133 - 25 = 1200314322101 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1200314322098 and 1200314322107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200314322113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14309485 + ... + 14393122.
It is an arithmetic number, because the mean of its divisors is an integer number (82663511040).
Almost surely, 21200314322133 is an apocalyptic number.
It is an amenable number.
1200314322133 is a deficient number, since it is larger than the sum of its proper divisors (122301854507).
1200314322133 is a wasteful number, since it uses less digits than its factorization.
1200314322133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28702728.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1200314322133 its reverse (3312234130021), we get a palindrome (4512548452154).
The spelling of 1200314322133 in words is "one trillion, two hundred billion, three hundred fourteen million, three hundred twenty-two thousand, one hundred thirty-three".
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