Base | Representation |
---|---|
bin | 10001011101111000010… |
… | …011110001100001111010 |
3 | 11020202012222011110222100 |
4 | 101131320103301201322 |
5 | 124131220431400424 |
6 | 2315230005404230 |
7 | 152501623264542 |
oct | 21357023614172 |
9 | 4222188143870 |
10 | 1200314325114 |
11 | 423061165213 |
12 | 174766a09676 |
13 | 8925c75cbb8 |
14 | 4214a18a322 |
15 | 213525c8dc9 |
hex | 117784f187a |
1200314325114 has 24 divisors (see below), whose sum is σ = 2656014678720. Its totient is φ = 391591907208.
The previous prime is 1200314325113. The next prime is 1200314325163. The reversal of 1200314325114 is 4115234130021.
1200314325114 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 3 + 143 + 2 + 511 + 4 = 666.
It is a super-2 number, since 2×12003143251142 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1200314325113) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 709404784 + ... + 709406475.
It is an arithmetic number, because the mean of its divisors is an integer number (110667278280).
Almost surely, 21200314325114 is an apocalyptic number.
1200314325114 is an abundant number, since it is smaller than the sum of its proper divisors (1455700353606).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1200314325114 is a wasteful number, since it uses less digits than its factorization.
1200314325114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1418811314 (or 1418811311 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 1200314325114 its reverse (4115234130021), we get a palindrome (5315548455135).
The spelling of 1200314325114 in words is "one trillion, two hundred billion, three hundred fourteen million, three hundred twenty-five thousand, one hundred fourteen".
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