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1200322232313 = 3400107410771
BaseRepresentation
bin10001011101111000110…
…001111011111111111001
311020202020112001012121120
4101131320301323333321
5124131224442413223
62315230451055453
7152502050426601
oct21357061737771
94222215035546
101200322232313
11423065675a96
121747695a1589
138926129b009
144214b247c01
152135313bbe3
hex11778c7bff9

1200322232313 has 4 divisors (see below), whose sum is σ = 1600429643088. Its totient is φ = 800214821540.

The previous prime is 1200322232299. The next prime is 1200322232339. The reversal of 1200322232313 is 3132322230021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200322232313 - 24 = 1200322232297 is a prime.

It is a super-2 number, since 2×12003222323132 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1200322232383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200053705383 + ... + 200053705388.

It is an arithmetic number, because the mean of its divisors is an integer number (400107410772).

Almost surely, 21200322232313 is an apocalyptic number.

It is an amenable number.

1200322232313 is a deficient number, since it is larger than the sum of its proper divisors (400107410775).

1200322232313 is an equidigital number, since it uses as much as digits as its factorization.

1200322232313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400107410774.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 1200322232313 its reverse (3132322230021), we get a palindrome (4332644462334).

The spelling of 1200322232313 in words is "one trillion, two hundred billion, three hundred twenty-two million, two hundred thirty-two thousand, three hundred thirteen".

Divisors: 1 3 400107410771 1200322232313