Base | Representation |
---|---|
bin | 10001011101111000110… |
… | …101010111011101011111 |
3 | 11020202020120201212200211 |
4 | 101131320311113131133 |
5 | 124131230210144411 |
6 | 2315230522233251 |
7 | 152502061162420 |
oct | 21357065273537 |
9 | 4222216655624 |
10 | 1200323131231 |
11 | 42306612a3a4 |
12 | 174769955827 |
13 | 89261524213 |
14 | 4214b3dd647 |
15 | 21353268221 |
hex | 11778d5775f |
1200323131231 has 16 divisors (see below), whose sum is σ = 1376396057344. Its totient is φ = 1025400389184.
The previous prime is 1200323131219. The next prime is 1200323131247. The reversal of 1200323131231 is 1321313230021.
It is a cyclic number.
It is not a de Polignac number, because 1200323131231 - 217 = 1200323000159 is a prime.
It is a super-2 number, since 2×12003231312312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200123131231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31599256 + ... + 31637218.
It is an arithmetic number, because the mean of its divisors is an integer number (86024753584).
Almost surely, 21200323131231 is an apocalyptic number.
1200323131231 is a deficient number, since it is larger than the sum of its proper divisors (176072926113).
1200323131231 is a wasteful number, since it uses less digits than its factorization.
1200323131231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52990.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1200323131231 its reverse (1321313230021), we get a palindrome (2521636361252).
The spelling of 1200323131231 in words is "one trillion, two hundred billion, three hundred twenty-three million, one hundred thirty-one thousand, two hundred thirty-one".
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