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1200324021122 = 2600162010561
BaseRepresentation
bin10001011101111000111…
…000110000101110000010
311020202020122102002101202
4101131320320300232002
5124131230422133442
62315230553301202
7152502101560022
oct21357070605602
94222218362352
101200324021122
11423066687a46
1217476a104802
1389261776295
144214b591a82
1521353391c32
hex11778e30b82

1200324021122 has 4 divisors (see below), whose sum is σ = 1800486031686. Its totient is φ = 600162010560.

The previous prime is 1200324021107. The next prime is 1200324021133. The reversal of 1200324021122 is 2211204230021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1042483882441 + 157840138681 = 1021021^2 + 397291^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1200324021094 and 1200324021103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300081005279 + ... + 300081005282.

Almost surely, 21200324021122 is an apocalyptic number.

1200324021122 is a deficient number, since it is larger than the sum of its proper divisors (600162010564).

1200324021122 is an equidigital number, since it uses as much as digits as its factorization.

1200324021122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600162010563.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1200324021122 its reverse (2211204230021), we get a palindrome (3411528251143).

The spelling of 1200324021122 in words is "one trillion, two hundred billion, three hundred twenty-four million, twenty-one thousand, one hundred twenty-two".

Divisors: 1 2 600162010561 1200324021122