12003400113130 has 16 divisors (see below), whose sum is σ = 21607183705824. Its totient is φ = 4801123711440.

The previous prime is 12003400113127. The next prime is 12003400113169. The reversal of 12003400113130 is 3131100430021.

It is a super-2 number, since 2×12003400113130² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12003400113098 and 12003400113107.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29328336 + ... + 29734795.

It is an arithmetic number, because the mean of its divisors is an integer number (1350448981614).

Almost surely, 2^{12003400113130} is an apocalyptic number.

12003400113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12003400113130 is a deficient number, since it is larger than the sum of its proper divisors (9603783592694).

12003400113130 is a wasteful number, since it uses less digits than its factorization.

12003400113130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59083461.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12003400113130 its reverse (3131100430021), we get a palindrome (15134500543151).

The spelling of 12003400113130 in words is "twelve trillion, three billion, four hundred million, one hundred thirteen thousand, one hundred thirty".