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12003411033001 is a prime number
BaseRepresentation
bin1010111010101100001100…
…0011001111101110101001
31120111111220100112112102001
42232223003003033232221
53033130441211024001
641310142500211001
72346134500221103
oct256530303175651
946444810475361
1012003411033001
113908688666443
12141a412099a61
13690bbc2a94cb
142d6d7aa1c573
1515c382607001
hexaeac30cfba9

12003411033001 has 2 divisors, whose sum is σ = 12003411033002. Its totient is φ = 12003411033000.

The previous prime is 12003411032971. The next prime is 12003411033007. The reversal of 12003411033001 is 10033011430021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10965528907776 + 1037882125225 = 3311424^2 + 1018765^2 .

It is a cyclic number.

It is not a de Polignac number, because 12003411033001 - 25 = 12003411032969 is a prime.

It is a super-2 number, since 2×120034110330012 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12003411033001.

It is not a weakly prime, because it can be changed into another prime (12003411033007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001705516500 + 6001705516501.

It is an arithmetic number, because the mean of its divisors is an integer number (6001705516501).

Almost surely, 212003411033001 is an apocalyptic number.

It is an amenable number.

12003411033001 is a deficient number, since it is larger than the sum of its proper divisors (1).

12003411033001 is an equidigital number, since it uses as much as digits as its factorization.

12003411033001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12003411033001 its reverse (10033011430021), we get a palindrome (22036422463022).

The spelling of 12003411033001 in words is "twelve trillion, three billion, four hundred eleven million, thirty-three thousand, one".