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12003441 = 34001147
BaseRepresentation
bin101101110010…
…100001110001
3211120211121220
4231302201301
511033102231
61105135253
7204012312
oct55624161
924524556
1012003441
1168593aa
12402a529
132643738
141846609
1510c1896
hexb72871

12003441 has 4 divisors (see below), whose sum is σ = 16004592. Its totient is φ = 8002292.

The previous prime is 12003437. The next prime is 12003449. The reversal of 12003441 is 14430021.

12003441 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12003441 - 22 = 12003437 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12003441.

It is not an unprimeable number, because it can be changed into a prime (12003449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000571 + ... + 2000576.

It is an arithmetic number, because the mean of its divisors is an integer number (4001148).

Almost surely, 212003441 is an apocalyptic number.

It is an amenable number.

12003441 is a deficient number, since it is larger than the sum of its proper divisors (4001151).

12003441 is an equidigital number, since it uses as much as digits as its factorization.

12003441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4001150.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 12003441 is about 3464.5982451072. The cubic root of 12003441 is about 228.9647295399.

Adding to 12003441 its reverse (14430021), we get a palindrome (26433462).

The spelling of 12003441 in words is "twelve million, three thousand, four hundred forty-one".

Divisors: 1 3 4001147 12003441