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12004013441 = 71714859063
BaseRepresentation
bin10110010110111111…
…01011010110000001
31010222120200001202102
423023133223112001
5144041011412231
65303051400145
7603320300510
oct131337532601
933876601672
1012004013441
1150aaa52a72
1223b0153055
131193c3b544
1481c384677
154a3cb4acb
hex2cb7eb581

12004013441 has 4 divisors (see below), whose sum is σ = 13718872512. Its totient is φ = 10289154372.

The previous prime is 12004013431. The next prime is 12004013537. The reversal of 12004013441 is 14431040021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12004013441 - 26 = 12004013377 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12004013431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857429525 + ... + 857429538.

It is an arithmetic number, because the mean of its divisors is an integer number (3429718128).

Almost surely, 212004013441 is an apocalyptic number.

It is an amenable number.

12004013441 is a deficient number, since it is larger than the sum of its proper divisors (1714859071).

12004013441 is an equidigital number, since it uses as much as digits as its factorization.

12004013441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1714859070.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 12004013441 its reverse (14431040021), we get a palindrome (26435053462).

The spelling of 12004013441 in words is "twelve billion, four million, thirteen thousand, four hundred forty-one".

Divisors: 1 7 1714859063 12004013441