1200404214003 has 4 divisors (see below), whose sum is σ = 1600538952008. Its totient is φ = 800269476000.

The previous prime is 1200404213999. The next prime is 1200404214019. The reversal of 1200404214003 is 3004124040021.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1200404214003 - 2² = 1200404213999 is a prime.

It is a super-3 number, since 3×1200404214003³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200404214403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200067368998 + ... + 200067369003.

It is an arithmetic number, because the mean of its divisors is an integer number (400134738002).

Almost surely, 2^{1200404214003} is an apocalyptic number.

1200404214003 is a deficient number, since it is larger than the sum of its proper divisors (400134738005).

1200404214003 is an equidigital number, since it uses as much as digits as its factorization.

1200404214003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400134738004.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 1200404214003 its reverse (3004124040021), we get a palindrome (4204528254024).

The spelling of 1200404214003 in words is "one trillion, two hundred billion, four hundred four million, two hundred fourteen thousand, three".