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120041131031002 = 2229262098539369
BaseRepresentation
bin11011010010110101000000…
…111110010011100111011010
3120202000211010211001220022001
4123102311000332103213122
5111213223214020443002
61103150045001351214
734166454063162346
oct3322650076234732
9522024124056261
10120041131031002
1135281181001615
1211568937a9850a
1351c9aa390623c
142190043936626
15dd282a5a2a87
hex6d2d40f939da

120041131031002 has 8 divisors (see below), whose sum is σ = 180847992165300. Its totient is φ = 59758466975904.

The previous prime is 120041131030981. The next prime is 120041131031023. The reversal of 120041131031002 is 200130131140021.

It is an interprime number because it is at equal distance from previous prime (120041131030981) and next prime (120041131031023).

It can be written as a sum of positive squares in 2 ways, for example, as 115476494508001 + 4564636523001 = 10745999^2 + 2136501^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131049269227 + ... + 131049270142.

Almost surely, 2120041131031002 is an apocalyptic number.

120041131031002 is a deficient number, since it is larger than the sum of its proper divisors (60806861134298).

120041131031002 is a wasteful number, since it uses less digits than its factorization.

120041131031002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262098539600.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 120041131031002 its reverse (200130131140021), we get a palindrome (320171262171023).

The spelling of 120041131031002 in words is "one hundred twenty trillion, forty-one billion, one hundred thirty-one million, thirty-one thousand, two".

Divisors: 1 2 229 458 262098539369 524197078738 60020565515501 120041131031002