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120041334113473 is a prime number
BaseRepresentation
bin11011010010110101001101…
…000101000000010011000001
3120202000211122222012120002001
4123102311031011000103001
5111213224123013112343
61103150121054224001
734166462110305463
oct3322651505002301
9522024588176061
10120041334113473
11352812756aa473
1211568993ab5001
1351c9b069cc596
1421900628bc133
15dd283d31a44d
hex6d2d4d1404c1

120041334113473 has 2 divisors, whose sum is σ = 120041334113474. Its totient is φ = 120041334113472.

The previous prime is 120041334113377. The next prime is 120041334113497. The reversal of 120041334113473 is 374311433140021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90881463713329 + 29159870400144 = 9533177^2 + 5399988^2 .

It is a cyclic number.

It is not a de Polignac number, because 120041334113473 - 221 = 120041332016321 is a prime.

It is not a weakly prime, because it can be changed into another prime (120041334213473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60020667056736 + 60020667056737.

It is an arithmetic number, because the mean of its divisors is an integer number (60020667056737).

Almost surely, 2120041334113473 is an apocalyptic number.

It is an amenable number.

120041334113473 is a deficient number, since it is larger than the sum of its proper divisors (1).

120041334113473 is an equidigital number, since it uses as much as digits as its factorization.

120041334113473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 37.

Adding to 120041334113473 its reverse (374311433140021), we get a palindrome (494352767253494).

The spelling of 120041334113473 in words is "one hundred twenty trillion, forty-one billion, three hundred thirty-four million, one hundred thirteen thousand, four hundred seventy-three".