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120099026379433 is a prime number
BaseRepresentation
bin11011010011101010111011…
…110011100010001010101001
3120202020100120122101022212011
4123103222323303202022221
5111220200301223120213
61103232421523515521
734203603555420553
oct3323527363421251
9522210518338764
10120099026379433
11352a3790463812
1211577bb4b28ba1
13520239c30726a
142192b76a8c4d3
15dd40b817003d
hex6d3abbce22a9

120099026379433 has 2 divisors, whose sum is σ = 120099026379434. Its totient is φ = 120099026379432.

The previous prime is 120099026379407. The next prime is 120099026379443. The reversal of 120099026379433 is 334973620990021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106032266056809 + 14066760322624 = 10297197^2 + 3750568^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120099026379433 is a prime.

It is a super-2 number, since 2×1200990263794332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120099026379443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60049513189716 + 60049513189717.

It is an arithmetic number, because the mean of its divisors is an integer number (60049513189717).

Almost surely, 2120099026379433 is an apocalyptic number.

It is an amenable number.

120099026379433 is a deficient number, since it is larger than the sum of its proper divisors (1).

120099026379433 is an equidigital number, since it uses as much as digits as its factorization.

120099026379433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13226976, while the sum is 58.

The spelling of 120099026379433 in words is "one hundred twenty trillion, ninety-nine billion, twenty-six million, three hundred seventy-nine thousand, four hundred thirty-three".