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120100110099953 is a prime number
BaseRepresentation
bin11011010011101011111100…
…011001100110010111110001
3120202020110101011121000221012
4123103223330121212113301
5111220210011141144303
61103233121235440305
734203642455041604
oct3323537431462761
9522213334530835
10120100110099953
11352a419716a005
1211578257a56095
1352025129a80c9
142192c3a99033b
15dd412d38c5d8
hex6d3afc6665f1

120100110099953 has 2 divisors, whose sum is σ = 120100110099954. Its totient is φ = 120100110099952.

The previous prime is 120100110099943. The next prime is 120100110099973. The reversal of 120100110099953 is 359990011001021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119936819755489 + 163290344464 = 10951567^2 + 404092^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120100110099953 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120100110099953.

It is not a weakly prime, because it can be changed into another prime (120100110099943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60050055049976 + 60050055049977.

It is an arithmetic number, because the mean of its divisors is an integer number (60050055049977).

Almost surely, 2120100110099953 is an apocalyptic number.

It is an amenable number.

120100110099953 is a deficient number, since it is larger than the sum of its proper divisors (1).

120100110099953 is an equidigital number, since it uses as much as digits as its factorization.

120100110099953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21870, while the sum is 41.

The spelling of 120100110099953 in words is "one hundred twenty trillion, one hundred billion, one hundred ten million, ninety-nine thousand, nine hundred fifty-three".