Base | Representation |
---|---|
bin | 110111111011010000… |
… | …1101001100011111001 |
3 | 102110222222120220022021 |
4 | 1233312201221203321 |
5 | 3431431113224423 |
6 | 131101230354441 |
7 | 11451123200452 |
oct | 1576641514371 |
9 | 373888526267 |
10 | 120100133113 |
11 | 46a30437664 |
12 | 1b33935ba21 |
13 | b42cb7662c |
14 | 5b54770129 |
15 | 31cdb8495d |
hex | 1bf68698f9 |
120100133113 has 2 divisors, whose sum is σ = 120100133114. Its totient is φ = 120100133112.
The previous prime is 120100133081. The next prime is 120100133117. The reversal of 120100133113 is 311331001021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113995367424 + 6104765689 = 337632^2 + 78133^2 .
It is a cyclic number.
It is not a de Polignac number, because 120100133113 - 25 = 120100133081 is a prime.
It is not a weakly prime, because it can be changed into another prime (120100133117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60050066556 + 60050066557.
It is an arithmetic number, because the mean of its divisors is an integer number (60050066557).
Almost surely, 2120100133113 is an apocalyptic number.
It is an amenable number.
120100133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
120100133113 is an equidigital number, since it uses as much as digits as its factorization.
120100133113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 120100133113 its reverse (311331001021), we get a palindrome (431431134134).
The spelling of 120100133113 in words is "one hundred twenty billion, one hundred million, one hundred thirty-three thousand, one hundred thirteen".
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