Base | Representation |
---|---|
bin | 1010111011000101100001… |
… | …1010111010111111100011 |
3 | 1120112011110022210001201020 |
4 | 2232301120122322333203 |
5 | 3033233403233341003 |
6 | 41313225404540523 |
7 | 2346465151461162 |
oct | 256613032727743 |
9 | 46464408701636 |
10 | 12010212012003 |
11 | 3910558636647 |
12 | 141b7ab851743 |
13 | 6917342ab93a |
14 | 2d7423d6d3d9 |
15 | 15c62e70bd53 |
hex | aec586bafe3 |
12010212012003 has 8 divisors (see below), whose sum is σ = 16020768153600. Its totient is φ = 8003231939208.
The previous prime is 12010212011981. The next prime is 12010212012023. The reversal of 12010212012003 is 30021021201021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12010212012003 - 241 = 9811188756451 is a prime.
It is a super-2 number, since 2×120102120120032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12010212012023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 894009363 + ... + 894022796.
It is an arithmetic number, because the mean of its divisors is an integer number (2002596019200).
Almost surely, 212010212012003 is an apocalyptic number.
12010212012003 is a deficient number, since it is larger than the sum of its proper divisors (4010556141597).
12010212012003 is a wasteful number, since it uses less digits than its factorization.
12010212012003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1788034401.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 12010212012003 its reverse (30021021201021), we get a palindrome (42031233213024).
The spelling of 12010212012003 in words is "twelve trillion, ten billion, two hundred twelve million, twelve thousand, three".
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