Base | Representation |
---|---|
bin | 10001011110100010100… |
… | …010111101001000011011 |
3 | 11020211001100120020122111 |
4 | 101132202202331020123 |
5 | 124134143333312432 |
6 | 2315424201533151 |
7 | 152525316421231 |
oct | 21364242751033 |
9 | 4224040506574 |
10 | 1201022947867 |
11 | 423395163a56 |
12 | 1749241a41b7 |
13 | 893434cacc2 |
14 | 421b632a951 |
15 | 21394901347 |
hex | 117a28bd21b |
1201022947867 has 2 divisors, whose sum is σ = 1201022947868. Its totient is φ = 1201022947866.
The previous prime is 1201022947829. The next prime is 1201022947889. The reversal of 1201022947867 is 7687492201021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201022947867 is a prime.
It is a super-2 number, since 2×12010229478672 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1201022947867.
It is not a weakly prime, because it can be changed into another prime (1201022977867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600511473933 + 600511473934.
It is an arithmetic number, because the mean of its divisors is an integer number (600511473934).
Almost surely, 21201022947867 is an apocalyptic number.
1201022947867 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201022947867 is an equidigital number, since it uses as much as digits as its factorization.
1201022947867 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 677376, while the sum is 49.
The spelling of 1201022947867 in words is "one trillion, two hundred one billion, twenty-two million, nine hundred forty-seven thousand, eight hundred sixty-seven".
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