Base | Representation |
---|---|
bin | 1010111011000101110110… |
… | …1011011010011110010011 |
3 | 1120112011200110202120011101 |
4 | 2232301131223122132103 |
5 | 3033234043324040311 |
6 | 41313242235325231 |
7 | 2346500302315216 |
oct | 256613553323623 |
9 | 46464613676141 |
10 | 12010300221331 |
11 | 39105a3404615 |
12 | 141b8152b0817 |
13 | 6917496547c9 |
14 | 2d743197177d |
15 | 15c637332ec1 |
hex | aec5dada793 |
12010300221331 has 2 divisors, whose sum is σ = 12010300221332. Its totient is φ = 12010300221330.
The previous prime is 12010300221229. The next prime is 12010300221341. The reversal of 12010300221331 is 13312200301021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12010300221331 - 211 = 12010300219283 is a prime.
It is a super-2 number, since 2×120103002213312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12010300221299 and 12010300221308.
It is not a weakly prime, because it can be changed into another prime (12010300221341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005150110665 + 6005150110666.
It is an arithmetic number, because the mean of its divisors is an integer number (6005150110666).
Almost surely, 212010300221331 is an apocalyptic number.
12010300221331 is a deficient number, since it is larger than the sum of its proper divisors (1).
12010300221331 is an equidigital number, since it uses as much as digits as its factorization.
12010300221331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12010300221331 its reverse (13312200301021), we get a palindrome (25322500522352).
The spelling of 12010300221331 in words is "twelve trillion, ten billion, three hundred million, two hundred twenty-one thousand, three hundred thirty-one".
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