Base | Representation |
---|---|
bin | 11011010011101111111110… |
… | …110011001100001110010011 |
3 | 120202020212120022002112222222 |
4 | 123103233332303030032103 |
5 | 111220242401001032243 |
6 | 1103235115342451255 |
7 | 34204155055636316 |
oct | 3323577663141623 |
9 | 522225508075888 |
10 | 120104445330323 |
11 | 352a60112aa823 |
12 | 11579067893b2b |
13 | 5202a53bb118c |
14 | 219312c64897d |
15 | dd42d3c80168 |
hex | 6d3bfeccc393 |
120104445330323 has 2 divisors, whose sum is σ = 120104445330324. Its totient is φ = 120104445330322.
The previous prime is 120104445330281. The next prime is 120104445330379. The reversal of 120104445330323 is 323033544401021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120104445330323 - 214 = 120104445313939 is a prime.
It is not a weakly prime, because it can be changed into another prime (120104445330383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60052222665161 + 60052222665162.
It is an arithmetic number, because the mean of its divisors is an integer number (60052222665162).
Almost surely, 2120104445330323 is an apocalyptic number.
120104445330323 is a deficient number, since it is larger than the sum of its proper divisors (1).
120104445330323 is an equidigital number, since it uses as much as digits as its factorization.
120104445330323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 120104445330323 its reverse (323033544401021), we get a palindrome (443137989731344).
The spelling of 120104445330323 in words is "one hundred twenty trillion, one hundred four billion, four hundred forty-five million, three hundred thirty thousand, three hundred twenty-three".
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