Base | Representation |
---|---|
bin | 10001011110100111001… |
… | …001101001110010100011 |
3 | 11020211020201221010012012 |
4 | 101132213021221302203 |
5 | 124134323122413443 |
6 | 2315440001423135 |
7 | 152530245154334 |
oct | 21364711516243 |
9 | 4224221833165 |
10 | 1201100201123 |
11 | 423424829519 |
12 | 17494603aaab |
13 | 893565090a4 |
14 | 421c26ba28b |
15 | 2139b5b1118 |
hex | 117a7269ca3 |
1201100201123 has 2 divisors, whose sum is σ = 1201100201124. Its totient is φ = 1201100201122.
The previous prime is 1201100201113. The next prime is 1201100201177. The reversal of 1201100201123 is 3211020011021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201100201123 - 222 = 1201096006819 is a prime.
It is a super-2 number, since 2×12011002011232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1201100201098 and 1201100201107.
It is not a weakly prime, because it can be changed into another prime (1201100201113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600550100561 + 600550100562.
It is an arithmetic number, because the mean of its divisors is an integer number (600550100562).
Almost surely, 21201100201123 is an apocalyptic number.
1201100201123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201100201123 is an equidigital number, since it uses as much as digits as its factorization.
1201100201123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1201100201123 its reverse (3211020011021), we get a palindrome (4412120212144).
The spelling of 1201100201123 in words is "one trillion, two hundred one billion, one hundred million, two hundred one thousand, one hundred twenty-three".
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