Search a number
-
+
12011023133313 = 34003674377771
BaseRepresentation
bin1010111011001000100011…
…0001000110101010000001
31120112020112212001021222020
42232302020301012222001
53033242033410231223
641313442102032053
72346524231054301
oct256621061065201
946466485037866
1012011023133313
113910934483036
12141b997418629
13691833356889
142d749d991601
1515c67aa2e1e3
hexaec88c46a81

12011023133313 has 4 divisors (see below), whose sum is σ = 16014697511088. Its totient is φ = 8007348755540.

The previous prime is 12011023133287. The next prime is 12011023133359. The reversal of 12011023133313 is 31333132011021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12011023133313 - 25 = 12011023133281 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12011023133513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001837188883 + ... + 2001837188888.

It is an arithmetic number, because the mean of its divisors is an integer number (4003674377772).

Almost surely, 212011023133313 is an apocalyptic number.

It is an amenable number.

12011023133313 is a deficient number, since it is larger than the sum of its proper divisors (4003674377775).

12011023133313 is an equidigital number, since it uses as much as digits as its factorization.

12011023133313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4003674377774.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 12011023133313 its reverse (31333132011021), we get a palindrome (43344155144334).

The spelling of 12011023133313 in words is "twelve trillion, eleven billion, twenty-three million, one hundred thirty-three thousand, three hundred thirteen".

Divisors: 1 3 4003674377771 12011023133313