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1201103444113 is a prime number
BaseRepresentation
bin10001011110100111010…
…110000001100010010001
311020211020222000212201221
4101132213112001202101
5124134324440202423
62315440155125041
7152530314552166
oct21364726014221
94224228025657
101201103444113
11423426643a81
12174947143781
13893570a3211
14421c2cc206d
152139ba01e5d
hex117a7581891

1201103444113 has 2 divisors, whose sum is σ = 1201103444114. Its totient is φ = 1201103444112.

The previous prime is 1201103444083. The next prime is 1201103444129. The reversal of 1201103444113 is 3114443011021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 788139123984 + 412964320129 = 887772^2 + 642623^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201103444113 - 225 = 1201069889681 is a prime.

It is a super-2 number, since 2×12011034441132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1201103444713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600551722056 + 600551722057.

It is an arithmetic number, because the mean of its divisors is an integer number (600551722057).

Almost surely, 21201103444113 is an apocalyptic number.

It is an amenable number.

1201103444113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201103444113 is an equidigital number, since it uses as much as digits as its factorization.

1201103444113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1201103444113 its reverse (3114443011021), we get a palindrome (4315546455134).

The spelling of 1201103444113 in words is "one trillion, two hundred one billion, one hundred three million, four hundred forty-four thousand, one hundred thirteen".