12011101131331 has 2 divisors, whose sum is σ = 12011101131332. Its totient is φ = 12011101131330.

The previous prime is 12011101131319. The next prime is 12011101131391. The reversal of 12011101131331 is 13313110111021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12011101131331 - 2¹¹ = 12011101129283 is a prime.

It is a super-2 number, since 2×12011101131331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12011101131299 and 12011101131308.

It is not a weakly prime, because it can be changed into another prime (12011101131301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005550565665 + 6005550565666.

It is an arithmetic number, because the mean of its divisors is an integer number (6005550565666).

Almost surely, 2^{12011101131331} is an apocalyptic number.

12011101131331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011101131331 is an equidigital number, since it uses as much as digits as its factorization.

12011101131331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 12011101131331 its reverse (13313110111021), we get a palindrome (25324211242352).

The spelling of 12011101131331 in words is "twelve trillion, eleven billion, one hundred one million, one hundred thirty-one thousand, three hundred thirty-one".