Base | Representation |
---|---|
bin | 11011010011110110000111… |
… | …100001000000111001111001 |
3 | 120202021111120110212020002202 |
4 | 123103312013201000321321 |
5 | 111220344344201330012 |
6 | 1103242125225035545 |
7 | 34204510251541532 |
oct | 3323660741007171 |
9 | 522244513766082 |
10 | 120111034011257 |
11 | 352a8892458283 |
12 | 1157a3a6325bb5 |
13 | 5203563c11753 |
14 | 21935956d5689 |
15 | dd456c3ebcc2 |
hex | 6d3d87840e79 |
120111034011257 has 2 divisors, whose sum is σ = 120111034011258. Its totient is φ = 120111034011256.
The previous prime is 120111034011233. The next prime is 120111034011313. The reversal of 120111034011257 is 752110430111021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100872073033081 + 19238960978176 = 10043509^2 + 4386224^2 .
It is a cyclic number.
It is not a de Polignac number, because 120111034011257 - 242 = 115712987500153 is a prime.
It is not a weakly prime, because it can be changed into another prime (120111034011557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055517005628 + 60055517005629.
It is an arithmetic number, because the mean of its divisors is an integer number (60055517005629).
Almost surely, 2120111034011257 is an apocalyptic number.
It is an amenable number.
120111034011257 is a deficient number, since it is larger than the sum of its proper divisors (1).
120111034011257 is an equidigital number, since it uses as much as digits as its factorization.
120111034011257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680, while the sum is 29.
Adding to 120111034011257 its reverse (752110430111021), we get a palindrome (872221464122278).
The spelling of 120111034011257 in words is "one hundred twenty trillion, one hundred eleven billion, thirty-four million, eleven thousand, two hundred fifty-seven".
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