Base | Representation |
---|---|
bin | 11011010011110110001011… |
… | …100000101000111100110010 |
3 | 120202021111202010221201120012 |
4 | 123103312023200220330302 |
5 | 111220400013330201002 |
6 | 1103242140021214522 |
7 | 34204512024245246 |
oct | 3323661340507462 |
9 | 522244663851505 |
10 | 120111101022002 |
11 | 352a8917267462 |
12 | 1157a404861442 |
13 | 5203574a7478c |
14 | 21935a057a426 |
15 | dd4573236d52 |
hex | 6d3d8b828f32 |
120111101022002 has 4 divisors (see below), whose sum is σ = 180166651533006. Its totient is φ = 60055550511000.
The previous prime is 120111101021993. The next prime is 120111101022007. The reversal of 120111101022002 is 200220101111021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 119335501998241 + 775599023761 = 10924079^2 + 880681^2 .
It is not an unprimeable number, because it can be changed into a prime (120111101022007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30027775255499 + ... + 30027775255502.
Almost surely, 2120111101022002 is an apocalyptic number.
120111101022002 is a deficient number, since it is larger than the sum of its proper divisors (60055550511004).
120111101022002 is an equidigital number, since it uses as much as digits as its factorization.
120111101022002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60055550511003.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 120111101022002 its reverse (200220101111021), we get a palindrome (320331202133023).
The spelling of 120111101022002 in words is "one hundred twenty trillion, one hundred eleven billion, one hundred one million, twenty-two thousand, two".
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