Base | Representation |
---|---|
bin | 1010111011001000111000… |
… | …0001001000011110011011 |
3 | 1120112020202222210121202121 |
4 | 2232302032001020132123 |
5 | 3033242223433034042 |
6 | 41313454530042111 |
7 | 2346526350564163 |
oct | 256621601103633 |
9 | 46466688717677 |
10 | 12011111221147 |
11 | 391097a1787a5 |
12 | 141ba00a19337 |
13 | 69184868935c |
14 | 2d74ab5615a3 |
15 | 15c68362e367 |
hex | aec8e04879b |
12011111221147 has 2 divisors, whose sum is σ = 12011111221148. Its totient is φ = 12011111221146.
The previous prime is 12011111221133. The next prime is 12011111221171. The reversal of 12011111221147 is 74112211111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12011111221147 - 215 = 12011111188379 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011111321147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005555610573 + 6005555610574.
It is an arithmetic number, because the mean of its divisors is an integer number (6005555610574).
Almost surely, 212011111221147 is an apocalyptic number.
12011111221147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011111221147 is an equidigital number, since it uses as much as digits as its factorization.
12011111221147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 25.
Adding to 12011111221147 its reverse (74112211111021), we get a palindrome (86123322332168).
The spelling of 12011111221147 in words is "twelve trillion, eleven billion, one hundred eleven million, two hundred twenty-one thousand, one hundred forty-seven".
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