Base | Representation |
---|---|
bin | 1010111011001000111101… |
… | …0100100110101110011011 |
3 | 1120112020211111222100000201 |
4 | 2232302033110212232123 |
5 | 3033242300033244003 |
6 | 41313501031043031 |
7 | 2346530034561526 |
oct | 256621724465633 |
9 | 46466744870021 |
10 | 12011133103003 |
11 | 3910990563981 |
12 | 141ba08210477 |
13 | 69185007b1b8 |
14 | 2d74b0419bbd |
15 | 15c685502b1d |
hex | aec8f526b9b |
12011133103003 has 2 divisors, whose sum is σ = 12011133103004. Its totient is φ = 12011133103002.
The previous prime is 12011133102977. The next prime is 12011133103027. The reversal of 12011133103003 is 30030133111021.
It is a strong prime.
It is an emirp because it is prime and its reverse (30030133111021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12011133103003 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011133103063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005566551501 + 6005566551502.
It is an arithmetic number, because the mean of its divisors is an integer number (6005566551502).
Almost surely, 212011133103003 is an apocalyptic number.
12011133103003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011133103003 is an equidigital number, since it uses as much as digits as its factorization.
12011133103003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 12011133103003 its reverse (30030133111021), we get a palindrome (42041266214024).
The spelling of 12011133103003 in words is "twelve trillion, eleven billion, one hundred thirty-three million, one hundred three thousand, three".
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