Base | Representation |
---|---|
bin | 10001011110101000010… |
… | …101100111010101010011 |
3 | 11020211022010101210112021 |
4 | 101132220111213111103 |
5 | 124134343222122003 |
6 | 2315441552312311 |
7 | 152530606341355 |
oct | 21365025472523 |
9 | 4224263353467 |
10 | 1201120114003 |
11 | 423434a9a347 |
12 | 174950842697 |
13 | 8935a68b964 |
14 | 421c51c10d5 |
15 | 2139d1e62bd |
hex | 117a8567553 |
1201120114003 has 2 divisors, whose sum is σ = 1201120114004. Its totient is φ = 1201120114002.
The previous prime is 1201120113989. The next prime is 1201120114037. The reversal of 1201120114003 is 3004110211021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201120114003 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201120114903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600560057001 + 600560057002.
It is an arithmetic number, because the mean of its divisors is an integer number (600560057002).
Almost surely, 21201120114003 is an apocalyptic number.
1201120114003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201120114003 is an equidigital number, since it uses as much as digits as its factorization.
1201120114003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1201120114003 its reverse (3004110211021), we get a palindrome (4205230325024).
The spelling of 1201120114003 in words is "one trillion, two hundred one billion, one hundred twenty million, one hundred fourteen thousand, three".
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