Base | Representation |
---|---|
bin | 10110010111110110… |
… | …00110010110100001 |
3 | 1011000002012021112121 |
4 | 23023323012112201 |
5 | 144044331430303 |
6 | 5303505424241 |
7 | 603435350332 |
oct | 131373062641 |
9 | 34002167477 |
10 | 12011201953 |
11 | 5104012893 |
12 | 23b263b081 |
13 | 11955874ba |
14 | 81d2d6289 |
15 | 4a47349bd |
hex | 2cbec65a1 |
12011201953 has 2 divisors, whose sum is σ = 12011201954. Its totient is φ = 12011201952.
The previous prime is 12011201921. The next prime is 12011201963. The reversal of 12011201953 is 35910211021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9539819584 + 2471382369 = 97672^2 + 49713^2 .
It is a cyclic number.
It is not a de Polignac number, because 12011201953 - 25 = 12011201921 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011201963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005600976 + 6005600977.
It is an arithmetic number, because the mean of its divisors is an integer number (6005600977).
Almost surely, 212011201953 is an apocalyptic number.
It is an amenable number.
12011201953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011201953 is an equidigital number, since it uses as much as digits as its factorization.
12011201953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 12011201953 its reverse (35910211021), we get a palindrome (47921412974).
The spelling of 12011201953 in words is "twelve billion, eleven million, two hundred one thousand, nine hundred fifty-three".
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