Base | Representation |
---|---|
bin | 11011010011110111000111… |
… | …001000000011101101011011 |
3 | 120202021121022211222120220002 |
4 | 123103313013020003231123 |
5 | 111220404040402222341 |
6 | 1103242423150523215 |
7 | 34204545560564132 |
oct | 3323670710035533 |
9 | 522247284876802 |
10 | 120112101210971 |
11 | 352a928a8aa211 |
12 | 1157a64380650b |
13 | 52036a404997c |
14 | 2193657336919 |
15 | dd45d0e5429b |
hex | 6d3dc7203b5b |
120112101210971 has 2 divisors, whose sum is σ = 120112101210972. Its totient is φ = 120112101210970.
The previous prime is 120112101210917. The next prime is 120112101211001. The reversal of 120112101210971 is 179012101211021.
Together with previous prime (120112101210917) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120112101210971 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (120112101290971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056050605485 + 60056050605486.
It is an arithmetic number, because the mean of its divisors is an integer number (60056050605486).
Almost surely, 2120112101210971 is an apocalyptic number.
120112101210971 is a deficient number, since it is larger than the sum of its proper divisors (1).
120112101210971 is an equidigital number, since it uses as much as digits as its factorization.
120112101210971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 29.
Adding to 120112101210971 its reverse (179012101211021), we get a palindrome (299124202421992).
The spelling of 120112101210971 in words is "one hundred twenty trillion, one hundred twelve billion, one hundred one million, two hundred ten thousand, nine hundred seventy-one".
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