Base | Representation |
---|---|
bin | 11011010011110111000111… |
… | …001000000011101110101011 |
3 | 120202021121022211222121000001 |
4 | 123103313013020003232223 |
5 | 111220404040402223201 |
6 | 1103242423150523431 |
7 | 34204545560564305 |
oct | 3323670710035653 |
9 | 522247284877001 |
10 | 120112101211051 |
11 | 352a928a8aa284 |
12 | 1157a643806577 |
13 | 52036a4049a11 |
14 | 2193657336975 |
15 | dd45d0e54301 |
hex | 6d3dc7203bab |
120112101211051 has 2 divisors, whose sum is σ = 120112101211052. Its totient is φ = 120112101211050.
The previous prime is 120112101211001. The next prime is 120112101211087. The reversal of 120112101211051 is 150112101211021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120112101211051 - 211 = 120112101209003 is a prime.
It is not a weakly prime, because it can be changed into another prime (120112101211001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056050605525 + 60056050605526.
It is an arithmetic number, because the mean of its divisors is an integer number (60056050605526).
Almost surely, 2120112101211051 is an apocalyptic number.
120112101211051 is a deficient number, since it is larger than the sum of its proper divisors (1).
120112101211051 is an equidigital number, since it uses as much as digits as its factorization.
120112101211051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 19.
Adding to 120112101211051 its reverse (150112101211021), we get a palindrome (270224202422072).
The spelling of 120112101211051 in words is "one hundred twenty trillion, one hundred twelve billion, one hundred one million, two hundred eleven thousand, fifty-one".
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