Base | Representation |
---|---|
bin | 10001011110101000011… |
… | …010001100011110111011 |
3 | 11020211022012122210122021 |
4 | 101132220122030132323 |
5 | 124134344024032442 |
6 | 2315442034135311 |
7 | 152530622502154 |
oct | 21365032143673 |
9 | 4224265583567 |
10 | 1201121314747 |
11 | 42343573a4a2 |
12 | 174951121537 |
13 | 8935a9bc363 |
14 | 421c541492b |
15 | 2139d381e67 |
hex | 117a868c7bb |
1201121314747 has 2 divisors, whose sum is σ = 1201121314748. Its totient is φ = 1201121314746.
The previous prime is 1201121314721. The next prime is 1201121314751. The reversal of 1201121314747 is 7474131211021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201121314747 - 227 = 1200987097019 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201121314787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600560657373 + 600560657374.
It is an arithmetic number, because the mean of its divisors is an integer number (600560657374).
Almost surely, 21201121314747 is an apocalyptic number.
1201121314747 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201121314747 is an equidigital number, since it uses as much as digits as its factorization.
1201121314747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9408, while the sum is 34.
Adding to 1201121314747 its reverse (7474131211021), we get a palindrome (8675252525768).
The spelling of 1201121314747 in words is "one trillion, two hundred one billion, one hundred twenty-one million, three hundred fourteen thousand, seven hundred forty-seven".
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