Base | Representation |
---|---|
bin | 110111111011100111… |
… | …1011101110001100001 |
3 | 102111000211012002101211 |
4 | 1233313033131301201 |
5 | 3431442202042312 |
6 | 131102340030121 |
7 | 11451330242155 |
oct | 1576717356141 |
9 | 374024162354 |
10 | 120112143457 |
11 | 46a371a0169 |
12 | 1b341392341 |
13 | b4324c0247 |
14 | 5b561b9065 |
15 | 31cec583a7 |
hex | 1bf73ddc61 |
120112143457 has 2 divisors, whose sum is σ = 120112143458. Its totient is φ = 120112143456.
The previous prime is 120112143379. The next prime is 120112143523. The reversal of 120112143457 is 754341211021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79664498001 + 40447645456 = 282249^2 + 201116^2 .
It is a cyclic number.
It is not a de Polignac number, because 120112143457 - 27 = 120112143329 is a prime.
It is not a weakly prime, because it can be changed into another prime (120112144457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056071728 + 60056071729.
It is an arithmetic number, because the mean of its divisors is an integer number (60056071729).
Almost surely, 2120112143457 is an apocalyptic number.
It is an amenable number.
120112143457 is a deficient number, since it is larger than the sum of its proper divisors (1).
120112143457 is an equidigital number, since it uses as much as digits as its factorization.
120112143457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 120112143457 its reverse (754341211021), we get a palindrome (874453354478).
The spelling of 120112143457 in words is "one hundred twenty billion, one hundred twelve million, one hundred forty-three thousand, four hundred fifty-seven".
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